exercise 1 question C

The frame 6 and 7 trying to communicate between each other. In frame 6 IP address 131.247.95.216 tries to communicate with the IP address 64.233.161.99 using HTTP protocol. Unfortunately the the packet send by IP 131.247.95.216 could not received by the IP 64.233.161.99, while sending the packet to the 64.233.161.99 by 131.247.95.216 gets the following problems.
Header checksum: 0x0000 [incorrect, should be 0x2276]
good checksum=False
bad checksum = True
source port: imyx (1143)
destination port: http (80)
flags : 0x18 (PSH, ACK)

Similarly in frame 7 the IP 64.233.161.99 sends the reply to the IP 131.247.95.216 using the TCP protocol. Followings are the process of the replying to the IP 131.247.95.216 by IP 64.233.161.99
Header Checksum: 0x075b [correct]
Good: True
Bad : False
Source port: HTTP (80)
Destination port: imyz (1143)
Flags: 0x10 (ACK)

From the above what we can found is that the IP 131.247.95.216 send the packet to the IP 64.233.161.99 which is not correct and the IP 64.233.161.99 sends the reply to the IP address 131.247.95.216 through the TCP and the reply as http > imyx [ACK] seq=1 ACK=493 win=7698 len=0. According to the analyzer the above description in the frame 7 replied to the frame 6 in correct even the request send by the IP 131.247.95.216 to the IP 64.233.161.99 was the wrong packet.