exercise 2 question H

The frame 141 and frame 142 got same source address and request graphic file from the same destination IP address . The information on both the frame is HTTP//1.0 200 ok (GIF89a). Following are the information from which the client can differentiate in the image requested by the same IP address with the same kind of information.

FRAME 141:

Transmission Control Protocol, src port: http (80), Dst port: stgxfws (1226), seq: 15765, Ack:3930, len:1045

FRAME 142

Transmission Control Protocol, src port: http (80), Dst port: slinkysearch (1225), seq: 25777, Ack:4253, len: 863

The above information show the different data hold by the two frame with same source IP address and the same information. The destination port for frame 141 and 142 are different and the seq and the acknowledgment were different to each other. By this difference the client can differentiate the about the graphic to match with the get statement in the frame.