exercise 3 question A

While comparing the TCP packet in the frame 3 and the frame 12 we found the following difference :
Frame 3:
Transmission Control Protocol, src port: omilink-port (3904), dst port:http (80), seq:0, len:0

Flags: 0x02 (SYN)
0... ....=congestion window reduced (CWR): not set
.0.. ....=ECN-echo: not Set
..0. ....=Urgent: not set
...0....=Acknowledgment: not set
.... 0...=Push:Not set
.... ..1.=Syn: set
.... ...0=Fin: not set
windows size= 65535
Checksum: 0x6405 [correct]
Options: (8 bytes)
Maximum segment size: 1406 bytes
NOP
NOP
SACK permitted


FRAME 12
Transmission Control Protocol, src port:mpl-gprs-port (3924), dst port: https (443), seq:1, ACK:1, Len=0
Flags : 0x10 (ACK)
0... .... = Congestion window reduced (CWR): Not set
.0.. .... = ECN-Echo: not set
..0. .... = Urgent: Not Set
...1 .... = Acknowledgment :set
.... 0... = Push : Not Set
.... .0.. =Reset: Not Set
.... ..0. = Syn: not set
.... ...0 = Fin: Not Set
Window size: 65535
Checksum: 0xa956 [correct]

[SEQ/ACK analysis]
This ACK was been segmented in frame 11. With the RTT to ACK and the Segment was: 0.000105000 seconds.

While comparing this two frame what we found is that the frame 3 is been segmented through byte process while the frame 12 is been segmented through the time process analysis. Frame 3 shows how much byte it will occur wile segment the and the frame 12 shows how many time they need to segment. In flags section the frame only sets for the SYN and the rest of the flags was not been set similarly in frame 12 Acknowledgment was been set and rest of the flag were not set.